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4.9x^2+7.1x=8
We move all terms to the left:
4.9x^2+7.1x-(8)=0
a = 4.9; b = 7.1; c = -8;
Δ = b2-4ac
Δ = 7.12-4·4.9·(-8)
Δ = 207.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7.1)-\sqrt{207.21}}{2*4.9}=\frac{-7.1-\sqrt{207.21}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7.1)+\sqrt{207.21}}{2*4.9}=\frac{-7.1+\sqrt{207.21}}{9.8} $
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